What is the answer to log_{10}(x^2)= 1/3 ?

The answer to log_{10}(x^2)= 1/3 is x=sqrt(\sqrt[3]{10)},x=-sqrt(\sqrt[3]{10)}

Solve for x: log_{10}(x^2)= 1/3

The solution is x=sqrt(\sqrt[3]{10)},x=-sqrt(\sqrt[3]{10)}

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lo g_{10} (x^{2}) = \frac{1}{3}

Decimal Notation

x = 1.46779 \dots, x = - 1.46779 \dots

Solution steps

lo g_{10} (x^{2}) = \frac{1}{3}

Apply log rules

Solve

x, ln (5 x - 1) - ln (4) = 3

lo g_{x} (50625) = 4

22 = ln (x) + x

5 lo g_{10} (x) = 3 \cdot 3

lo g_{x} (3) + 16 lo g_{81} (x) = 5

What is the answer to log_{10}(x^2)= 1/3 ?
The answer to log_{10}(x^2)= 1/3 is x=sqrt(\sqrt[3]{10)},x=-sqrt(\sqrt[3]{10)}
Solve for x: log_{10}(x^2)= 1/3
The solution is x=sqrt(\sqrt[3]{10)},x=-sqrt(\sqrt[3]{10)}