What are the solutions to the equation -4x^2+x^2+147=0 ?

The solutions to the equation -4x^2+x^2+147=0 are x=7,x=-7

Find the zeros of -4x^2+x^2+147=0

The zeros of -4x^2+x^2+147=0 are x=7,x=-7

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- 4 x^{2} + x^{2} + 147 = 0

x = 7, x = - 7

Solution steps

- 4 x^{2} + x^{2} + 147 = 0

Move

147

to the right side

- 4 x^{2} + x^{2} = - 147

Add similar elements:

- 4 x^{2} + x^{2} = - 3 x^{2}

- 3 x^{2} = - 147

Divide both sides by

- 3

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

- 4 < 5 - 3 x \leq 17

\frac{8}{3} \cdot 2

x^{2} - 120 x - 3600 = 0

\frac{( - \frac{15}{17} )}{( - \frac{8}{17} )}

(\frac{5}{2})^{x} + \frac{125}{8} \cdot (\frac{5}{2})^{x}

What are the solutions to the equation -4x^2+x^2+147=0 ?
The solutions to the equation -4x^2+x^2+147=0 are x=7,x=-7
Find the zeros of -4x^2+x^2+147=0
The zeros of -4x^2+x^2+147=0 are x=7,x=-7