What is the answer to log_{4}(x-3)+log_{4}(x)=1 ?

The answer to log_{4}(x-3)+log_{4}(x)=1 is x=4

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log_{4}(x-3)+log_{4}(x)=1

lo g_{4} (x - 3) + lo g_{4} (x) = 1

x = 4

Solution steps

lo g_{4} (x - 3) + lo g_{4} (x) = 1

Apply log rules

(x - 3) x = 4

Solve

(x - 3) x = 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

False

The solution is

x = 4

lo g_{4} (x) + 4 = 9

3 - ln (x) = 2

4 lo g_{25} (x) = 20 lo g_{5} (x)

ln (y + 2) = ln (42 + 2)

lo g_{x} (9) = 81

What is the answer to log_{4}(x-3)+log_{4}(x)=1 ?
The answer to log_{4}(x-3)+log_{4}(x)=1 is x=4
Solve for x: log_{4}(x-3)+log_{4}(x)=1
The solution is x=4