What is the answer to solvefor x,log_{2}(x^2y)=-3 ?

The answer to solvefor x,log_{2}(x^2y)=-3 is x= 1/(2sqrt(2)\sqrt{y)},x=-1/(2sqrt(2)\sqrt{y)}

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solvefor x,log_{2}(x^2y)=-3

solve for

x, lo g_{2} (x^{2} y) = - 3

x = \frac{1}{2 2 y}, x = - \frac{1}{2 2 y}

Solution steps

lo g_{2} (x^{2} y) = - 3

Apply log rules

x^{2} y = \frac{1}{8}

Solve

x^{2} y = \frac{1}{8} : x = \frac{1}{2 2 y}, x = - \frac{1}{2 2 y}

x = \frac{1}{2 2 y}, x = - \frac{1}{2 2 y}

lo g_{27} (x) = \frac{- 2}{3}

8.89 = lo g_{10} (\frac{1}{x})

lo g_{10} (2 x + 5) = lo g_{10} (7)

x, 3.07 = - lo g_{10} (x)

ln (3 x - 5) = 0

What is the answer to solvefor x,log_{2}(x^2y)=-3 ?
The answer to solvefor x,log_{2}(x^2y)=-3 is x= 1/(2sqrt(2)\sqrt{y)},x=-1/(2sqrt(2)\sqrt{y)}