What is the answer to log_{3}(4x-5)=log_{3}(x+3) ?

The answer to log_{3}(4x-5)=log_{3}(x+3) is x= 8/3

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log_{3}(4x-5)=log_{3}(x+3)

lo g_{3} (4 x - 5) = lo g_{3} (x + 3)

x = \frac{8}{3}

Decimal Notation

x = 2.66666 \dots

Solution steps

lo g_{3} (4 x - 5) = lo g_{3} (x + 3)

Apply log rules

4 x - 5 = x + 3

Solve

4 x - 5 = x + 3 : x = \frac{8}{3}

x = \frac{8}{3}

Verify Solutions:

x = \frac{8}{3}

True

The solution is

x = \frac{8}{3}

20 lo g_{10} (x) = 29.5

lo g_{3} (x + 58) = lo g_{3} (x + 2) + 2

lo g_{6} (x + 5) = 36

ln (2 x + 1) = 0

3 lo g_{2} (\frac{3}{x}) = 9

What is the answer to log_{3}(4x-5)=log_{3}(x+3) ?
The answer to log_{3}(4x-5)=log_{3}(x+3) is x= 8/3
Solve for x: log_{3}(4x-5)=log_{3}(x+3)
The solution is x= 8/3