What is the answer to 155=40log_{10}(500t+1) ?

The answer to 155=40log_{10}(500t+1) is t=(1000*10^{7/8}-1)/(500)

Solve for t: 155=40log_{10}(500t+1)

The solution is t=(1000*10^{7/8}-1)/(500)

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155 = 40 lo g_{10} (500 t + 1)

t = \frac{1000 \cdot 1 0 ^{\frac{7}{8}} - 1}{500}

Decimal Notation

t = 14.99588 \dots

Solution steps

155 = 40 lo g_{10} (500 t + 1)

Switch sides

40 lo g_{10} (500 t + 1) = 155

Divide both sides by

40

lo g_{10} (500 t + 1) = \frac{31}{8}

Apply log rules

500 t + 1 = 1000 \cdot 1 0^{\frac{7}{8}}

Solve

500 t + 1 = 1000 \cdot 1 0^{\frac{7}{8}} : t = \frac{1000 \cdot 1 0 ^{\frac{7}{8}} - 1}{500}

t = \frac{1000 \cdot 1 0 ^{\frac{7}{8}} - 1}{500}

Verify Solutions:

t = \frac{1000 \cdot 1 0 ^{\frac{7}{8}} - 1}{500}

True

The solution is

t = \frac{1000 \cdot 1 0 ^{\frac{7}{8}} - 1}{500}

ln (x) = 2 + ln (3)

64 n \cdot lo g_{2} (n) = 8 n^{2}

0 = ln (4 x)

x, ln (x + 1) + ln (2 y) = k

lo g_{5} ((x + 2)^{2}) = 2

What is the answer to 155=40log_{10}(500t+1) ?
The answer to 155=40log_{10}(500t+1) is t=(1000*10^{7/8}-1)/(500)
Solve for t: 155=40log_{10}(500t+1)
The solution is t=(1000*10^{7/8}-1)/(500)