What is the answer to log_{2}(2^{x+1}-8)=x ?

The answer to log_{2}(2^{x+1}-8)=x is x=3

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log_{2}(2^{x+1}-8)=x

lo g_{2} (2^{x + 1} - 8) = x

x = 3

Solution steps

lo g_{2} (2^{x + 1} - 8) = x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (2^{x + 1} - 8)} = 2^{x}

Simplify

2^{l o g_{2} (2^{x + 1} - 8)} : 2^{x + 1} - 8

2^{x + 1} - 8 = 2^{x}

Solve

2^{x + 1} - 8 = 2^{x} : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

ln (x) = 3.53

ln (x) = 3.57

ln (8 x - 1) = - 2

ln (1 + x) = 4

ln (5 x^{2}) - ln (5 x) = 1

What is the answer to log_{2}(2^{x+1}-8)=x ?
The answer to log_{2}(2^{x+1}-8)=x is x=3
Solve for x: log_{2}(2^{x+1}-8)=x
The solution is x=3