What is the answer to log_{2}(x^2-16)=0 ?

The answer to log_{2}(x^2-16)=0 is x=sqrt(17),x=-sqrt(17)

Solve for x: log_{2}(x^2-16)=0

The solution is x=sqrt(17),x=-sqrt(17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x^{2} - 16) = 0

x = 17, x = - 17

Decimal Notation

x = 4.12310 \dots, x = - 4.12310 \dots

Solution steps

lo g_{2} (x^{2} - 16) = 0

Apply log rules

x^{2} - 16 = 1

Solve

x^{2} - 16 = 1 : x = 17, x = - 17

x = 17, x = - 17

lo g_{2} (x + 2) - lo g_{2} (x - 1) = 2

2 ln (x) - ln (x + 5) + ln (3) = ln (x)

ln (3 x + 6) + ln (2) = ln (63)

ln (2 - 3 x) = 9

- 3 ln (x + 1) = 2

What is the answer to log_{2}(x^2-16)=0 ?
The answer to log_{2}(x^2-16)=0 is x=sqrt(17),x=-sqrt(17)
Solve for x: log_{2}(x^2-16)=0
The solution is x=sqrt(17),x=-sqrt(17)