What are the solutions to the equation (2w-1)w=21 ?

The solutions to the equation (2w-1)w=21 are w= 7/2 ,w=-3

Find the zeros of (2w-1)w=21

The zeros of (2w-1)w=21 are w= 7/2 ,w=-3

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(2 w - 1) w = 21

w = \frac{7}{2}, w = - 3

Solution steps

(2 w - 1) w = 21

Expand

(2 w - 1) w : 2 w^{2} - w

2 w^{2} - w = 21

Move

21

to the left side

2 w^{2} - w - 21 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 21) = 13

w_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 2}, w_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 2}

w = \frac{- ( - 1 ) + 13}{2 \cdot 2} : \frac{7}{2}

w = \frac{- ( - 1 ) - 13}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = \frac{7}{2}, w = - 3

(x - 2)^{3} + 8 y^{3}

\frac{3}{5 - 2 x} \leq 2

x + 4 = - 3

6 x^{2} - 48 = - 12 x

x^{2} - 4 x + 40 = 0

What are the solutions to the equation (2w-1)w=21 ?
The solutions to the equation (2w-1)w=21 are w= 7/2 ,w=-3
Find the zeros of (2w-1)w=21
The zeros of (2w-1)w=21 are w= 7/2 ,w=-3