What is the answer to ln((x+1)^2)=2ln(x+1) ?

The answer to ln((x+1)^2)=2ln(x+1) is x>-1

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ln((x+1)^2)=2ln(x+1)

ln ((x + 1)^{2}) = 2 ln (x + 1)

x > - 1

Solution steps

ln ((x + 1)^{2}) = 2 ln (x + 1)

Apply log rules

x + 1 = x + 1

Both sides are equal

True for all x

Verify Solutions:

x > - 1

The solution is

x > - 1

x, t = 2 ln (16 x)

10 lo g_{10} (x) = 52

10 lo g_{10} (x) = 50

lo g_{16} (x) = 2 + lo g_{16} (2)

2 lo g_{4} (x + 1) = 5

What is the answer to ln((x+1)^2)=2ln(x+1) ?
The answer to ln((x+1)^2)=2ln(x+1) is x>-1
Solve for x: ln((x+1)^2)=2ln(x+1)
The solution is x>-1