What is the answer to 6log_{5}(4p-3)-2=16 ?

The answer to 6log_{5}(4p-3)-2=16 is p=32

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6log_{5}(4p-3)-2=16

6 lo g_{5} (4 p - 3) - 2 = 16

p = 32

Solution steps

6 lo g_{5} (4 p - 3) - 2 = 16

Move

2

to the right side

6 lo g_{5} (4 p - 3) = 18

Divide both sides by

6

lo g_{5} (4 p - 3) = 3

Apply log rules

4 p - 3 = 125

Solve

4 p - 3 = 125 : p = 32

p = 32

Verify Solutions:

p = 32

True

The solution is

p = 32

10 lo g_{10} (x) = 25

lo g_{7} (x - 5) = lo g_{7} (3)

lo g_{10} (t^{7}) = 5

10 lo g_{10} (x) = 99

lo g_{e} (x) = 2.7

What is the answer to 6log_{5}(4p-3)-2=16 ?
The answer to 6log_{5}(4p-3)-2=16 is p=32
Solve for p: 6log_{5}(4p-3)-2=16
The solution is p=32