What is the answer to log_{5}(x)+log_{5}(2x+3)=1 ?

The answer to log_{5}(x)+log_{5}(2x+3)=1 is x=1

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log_{5}(x)+log_{5}(2x+3)=1

lo g_{5} (x) + lo g_{5} (2 x + 3) = 1

x = 1

Solution steps

lo g_{5} (x) + lo g_{5} (2 x + 3) = 1

Apply log rules

x (2 x + 3) = 5

Solve

x (2 x + 3) = 5 : x = 1, x = - \frac{5}{2}

x = 1, x = - \frac{5}{2}

Verify Solutions:

x = 1

True

, x = - \frac{5}{2}

False

The solution is

x = 1

lo g_{10} (x) = 0.9469

ln (u (x) x) = ln (u (x)) + ln (x)

1.4 lo g_{e} (x) + 14.1 = 17.6

ln (2) - ln (- 1 + c) = 0

lo g_{5} (2 x - 2) = 2

What is the answer to log_{5}(x)+log_{5}(2x+3)=1 ?
The answer to log_{5}(x)+log_{5}(2x+3)=1 is x=1
Solve for x: log_{5}(x)+log_{5}(2x+3)=1
The solution is x=1