What is the answer to ln(x+2)+ln(x-1)=1 ?

The answer to ln(x+2)+ln(x-1)=1 is x=(-1+sqrt(4e+9))/2

Solve for x: ln(x+2)+ln(x-1)=1

The solution is x=(-1+sqrt(4e+9))/2

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ln (x + 2) + ln (x - 1) = 1

x = \frac{- 1 + 4 e + 9}{2}

Decimal Notation

x = 1.72896 \dots

Solution steps

ln (x + 2) + ln (x - 1) = 1

Apply log rules

(x + 2) (x - 1) = e

Solve

(x + 2) (x - 1) = e : x = \frac{- 1 + 4 e + 9}{2}, x = \frac{- 1 - 4 e + 9}{2}

x = \frac{- 1 + 4 e + 9}{2}, x = \frac{- 1 - 4 e + 9}{2}

Verify Solutions:

x = \frac{- 1 + 4 e + 9}{2}

True

, x = \frac{- 1 - 4 e + 9}{2}

False

The solution is

x = \frac{- 1 + 4 e + 9}{2}

lo g_{5} (3 x - 1) = 2

- 11 = ln (0^{2} + x)

- ln (126) = 4 ln (p) + 5 ln (1 - p)

- 3 lo g_{3} (2) = lo g_{3} (x)

lo g_{3} (x) = 2 + 2 lo g_{3} (x)

What is the answer to ln(x+2)+ln(x-1)=1 ?
The answer to ln(x+2)+ln(x-1)=1 is x=(-1+sqrt(4e+9))/2
Solve for x: ln(x+2)+ln(x-1)=1
The solution is x=(-1+sqrt(4e+9))/2