What is the answer to de=ln^3(x^2+1) ?

The answer to de=ln^3(x^2+1) is No Solution for x\in\mathbb{R}

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de=ln^3(x^2+1)

d e = ln^{3} (x^{2} + 1)

No Solution for x \in R

Solution steps

d e = ln^{3} (x^{2} + 1)

Rewrite the equation with

ln (x^{2} + 1) = u

d e = u^{3}

Solve

Substitute back

u = ln (x^{2} + 1),

solve for

x

Solve

Verify Solutions:

False

The solution is

No Solution for x \in R

x, 8 ln (x) = 2

0.69897 = lo g_{10} (x)

ln (2 x^{2} - 11) = 1.946

2 lo g_{3} (1 - x) = 6

ln (x) = \frac{2}{3} ln (8)

What is the answer to de=ln^3(x^2+1) ?
The answer to de=ln^3(x^2+1) is No Solution for x\in\mathbb{R}