What is the answer to 0=1+log_{5}(x-4) ?

The answer to 0=1+log_{5}(x-4) is x= 21/5

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0=1+log_{5}(x-4)

0 = 1 + lo g_{5} (x - 4)

x = \frac{21}{5}

Decimal Notation

x = 4.2

Solution steps

0 = 1 + lo g_{5} (x - 4)

Switch sides

1 + lo g_{5} (x - 4) = 0

Move

1

to the right side

lo g_{5} (x - 4) = - 1

Apply log rules

x - 4 = \frac{1}{5}

Solve

x - 4 = \frac{1}{5} : x = \frac{21}{5}

x = \frac{21}{5}

Verify Solutions:

x = \frac{21}{5}

True

The solution is

x = \frac{21}{5}

2 ln (X) - 3 = ln (A^{2} - e^{3})

20 \cdot lo g_{10} (x \cdot 2) = 20

x, 4 ln (8 x - 2) + 2 = 10

lo g_{8} (a^{6}) = lo g_{8} (x)

8 + lo g_{6} (- 4 x) = 10

What is the answer to 0=1+log_{5}(x-4) ?
The answer to 0=1+log_{5}(x-4) is x= 21/5
Solve for x: 0=1+log_{5}(x-4)
The solution is x= 21/5