What is the answer to 2log_{4}(x)-log_{4}(3x-5)=1 ?

The answer to 2log_{4}(x)-log_{4}(3x-5)=1 is x=10,x=2

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2log_{4}(x)-log_{4}(3x-5)=1

2 lo g_{4} (x) - lo g_{4} (3 x - 5) = 1

x = 10, x = 2

Solution steps

2 lo g_{4} (x) - lo g_{4} (3 x - 5) = 1

Apply log rules

x^{2} = 4 (3 x - 5)

Solve

x^{2} = 4 (3 x - 5) : x = 10, x = 2

x = 10, x = 2

Verify Solutions:

x = 10

True

, x = 2

True

The solutions are

x = 10, x = 2

2.88 = - lo g_{10} (x)

lo g_{3} (2 x + 1) - lo g_{3} (x + 7) = 1

ln (x) = - \frac{1}{40}

ln (x + 2.8) = 1.6

4 \cdot ln (x) = 2.0706

What is the answer to 2log_{4}(x)-log_{4}(3x-5)=1 ?
The answer to 2log_{4}(x)-log_{4}(3x-5)=1 is x=10,x=2
Solve for x: 2log_{4}(x)-log_{4}(3x-5)=1
The solution is x=10,x=2