What is the answer to solvefor x,ln(xy)+4x=35 ?

The answer to solvefor x,ln(xy)+4x=35 is x=(\W((4e^{35})/y))/(4)

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solvefor x,ln(xy)+4x=35

solve for

x, ln (x y) + 4 x = 35

x = \frac{W ( \frac{4 e ^{35}}{y} )}{4}

Solution steps

ln (x y) + 4 x = 35

Move

4 x

to the right side

ln (x y) = 35 - 4 x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x y)} = e^{35 - 4 x}

Simplify

e^{l n (x y)} : x y

x y = e^{35 - 4 x}

Solve

x y = e^{35 - 4 x} : x = \frac{W ( \frac{4 e ^{35}}{y} )}{4}

x = \frac{W ( \frac{4 e ^{35}}{y} )}{4}

Verify Solutions:

x = \frac{W ( \frac{4 e ^{35}}{y} )}{4}

True

The solution is

x = \frac{W ( \frac{4 e ^{35}}{y} )}{4}

x, ln (x y) + 4 x = 45

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What is the answer to solvefor x,ln(xy)+4x=35 ?
The answer to solvefor x,ln(xy)+4x=35 is x=(\W((4e^{35})/y))/(4)