What is the answer to log_{3}(x+3)+log_{3}(x)=2 ?

The answer to log_{3}(x+3)+log_{3}(x)=2 is x=(-3+3sqrt(5))/2

Solve for x: log_{3}(x+3)+log_{3}(x)=2

The solution is x=(-3+3sqrt(5))/2

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lo g_{3} (x + 3) + lo g_{3} (x) = 2

x = \frac{- 3 + 3 5}{2}

Decimal Notation

x = 1.85410 \dots

Solution steps

lo g_{3} (x + 3) + lo g_{3} (x) = 2

Apply log rules

(x + 3) x = 9

Solve

(x + 3) x = 9 : x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

Verify Solutions:

x = \frac{- 3 + 3 5}{2}

True

, x = \frac{- 3 - 3 5}{2}

False

The solution is

x = \frac{- 3 + 3 5}{2}

x, ln (x) = 2 y

a = ln (x)

lo g_{3} (∣ x - 2 ∣) = 2

lo g_{3} (4 x^{2}) + lo g_{3} (4) = 4

4 lo g_{a} (x) = 3 lo g_{10} (b)

What is the answer to log_{3}(x+3)+log_{3}(x)=2 ?
The answer to log_{3}(x+3)+log_{3}(x)=2 is x=(-3+3sqrt(5))/2
Solve for x: log_{3}(x+3)+log_{3}(x)=2
The solution is x=(-3+3sqrt(5))/2