What is the answer to log_{10}(5)(2x+3)=log_{8}(x) ?

The answer to log_{10}(5)(2x+3)=log_{8}(x) is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(5)(2x+3)=log_{8}(x)

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (5) (2 x + 3) = lo g_{8} (x)

No Solution for x \in R

Solution steps

lo g_{10} (5) (2 x + 3) = lo g_{8} (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

8^{l o g_{10} (5) (2 x + 3)} = 8^{l o g_{8} (x)}

Simplify

8^{l o g_{8} (x)} : x

8^{l o g_{10} (5) (2 x + 3)} = x

Solve

8^{l o g_{10} (5) (2 x + 3)} = x :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (x) + lo g_{100} (x) = 3

lo g_{x} (2) = 2

lo g_{x} (2) = 6

lo g_{2} (x + 4) = - 2

3 + lo g_{2} (x + 2) = 3

What is the answer to log_{10}(5)(2x+3)=log_{8}(x) ?
The answer to log_{10}(5)(2x+3)=log_{8}(x) is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(5)(2x+3)=log_{8}(x)
The solution is No Solution for x\in\mathbb{R}