What is the answer to log_{7}(4x)+4log_{7}(2)=2 ?

The answer to log_{7}(4x)+4log_{7}(2)=2 is x= 49/64

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log_{7}(4x)+4log_{7}(2)=2

lo g_{7} (4 x) + 4 lo g_{7} (2) = 2

x = \frac{49}{64}

Decimal Notation

x = 0.765625

Solution steps

lo g_{7} (4 x) + 4 lo g_{7} (2) = 2

Move

4 lo g_{7} (2)

to the right side

lo g_{7} (4 x) = 2 - 4 lo g_{7} (2)

Apply log rules

4 x = \frac{49}{16}

Solve

4 x = \frac{49}{16} : x = \frac{49}{64}

x = \frac{49}{64}

Verify Solutions:

x = \frac{49}{64}

True

The solution is

x = \frac{49}{64}

lo g_{10} (x) = \frac{13}{5}

- 7 + lo g_{3} (x - 1) = - 5

x, 2.59 = - lo g_{10} (x)

lo g_{4} (x - 6) + lo g_{4} (x) = 2

lo g_{2} (x) = 15

What is the answer to log_{7}(4x)+4log_{7}(2)=2 ?
The answer to log_{7}(4x)+4log_{7}(2)=2 is x= 49/64
Solve for x: log_{7}(4x)+4log_{7}(2)=2
The solution is x= 49/64