What is the answer to log_{4}(X+1)=log_{2}(X-1) ?

The answer to log_{4}(X+1)=log_{2}(X-1) is X=3

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log_{4}(X+1)=log_{2}(X-1)

lo g_{4} (X + 1) = lo g_{2} (X - 1)

X = 3

Solution steps

lo g_{4} (X + 1) = lo g_{2} (X - 1)

Apply log rules

X + 1 = (X - 1)^{2}

Solve

X + 1 = (X - 1)^{2} : X = 3, X = 0

X = 3, X = 0

Verify Solutions:

X = 3

True

, X = 0

False

The solution is

X = 3

lo g_{10} (6 x) = lo g_{10} (6 x + 1)

lo g_{2} (\frac{x}{2}) = 1.9159300000000 \dots

lo g_{2} (x) = 40

ln (x^{2}) - 2 ln (x) - 3 = 0

lo g_{4} (7 x + 15) = 3

What is the answer to log_{4}(X+1)=log_{2}(X-1) ?
The answer to log_{4}(X+1)=log_{2}(X-1) is X=3
Solve for X: log_{4}(X+1)=log_{2}(X-1)
The solution is X=3