What is the answer to solvefor x,2log_{3}(3x-7)+1=9 ?

The answer to solvefor x,2log_{3}(3x-7)+1=9 is x= 88/3

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solvefor x,2log_{3}(3x-7)+1=9

solve for

x, 2 lo g_{3} (3 x - 7) + 1 = 9

x = \frac{88}{3}

Decimal Notation

x = 29.33333 \dots

Solution steps

2 lo g_{3} (3 x - 7) + 1 = 9

Move

1

to the right side

2 lo g_{3} (3 x - 7) = 8

Divide both sides by

2

lo g_{3} (3 x - 7) = 4

Apply log rules

3 x - 7 = 81

Solve

3 x - 7 = 81 : x = \frac{88}{3}

x = \frac{88}{3}

Verify Solutions:

x = \frac{88}{3}

True

The solution is

x = \frac{88}{3}

1.8 = - lo g_{10} (x)

- 9 + lo g_{2} (2 x) = - 6

lo g_{2 x + 1} (49) = 2

lo g_{7} (13 x + 20) = lo g_{7} (72)

n = lo g_{2} (n)

What is the answer to solvefor x,2log_{3}(3x-7)+1=9 ?
The answer to solvefor x,2log_{3}(3x-7)+1=9 is x= 88/3