What is the answer to 2log_{4}(3x-1)+5=7 ?

The answer to 2log_{4}(3x-1)+5=7 is x= 5/3

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2log_{4}(3x-1)+5=7

2 lo g_{4} (3 x - 1) + 5 = 7

x = \frac{5}{3}

Decimal Notation

x = 1.66666 \dots

Solution steps

2 lo g_{4} (3 x - 1) + 5 = 7

Move

5

to the right side

2 lo g_{4} (3 x - 1) = 2

Divide both sides by

2

lo g_{4} (3 x - 1) = 1

Apply log rules

3 x - 1 = 4

Solve

3 x - 1 = 4 : x = \frac{5}{3}

x = \frac{5}{3}

Verify Solutions:

x = \frac{5}{3}

True

The solution is

x = \frac{5}{3}

lo g_{7} (5 y + 4) = 2

D = 12 - ln (p)

lo g_{3} (2 x) = 5

4.86 = - lo g_{10} (x)

z + ln (1 + z) = 0

What is the answer to 2log_{4}(3x-1)+5=7 ?
The answer to 2log_{4}(3x-1)+5=7 is x= 5/3
Solve for x: 2log_{4}(3x-1)+5=7
The solution is x= 5/3