What is the answer to log_{a}(x)=-1/(ln(a)) ?

The answer to log_{a}(x)=-1/(ln(a)) is x=a^{-1/(ln(a))}

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log_{a}(x)=-1/(ln(a))

lo g_{a} (x) = - \frac{1}{ln ( a )}

x = a^{- \frac{1}{l n ( a )}}

Solution steps

lo g_{a} (x) = - \frac{1}{ln ( a )}

Apply log rules

x = a^{- \frac{1}{l n ( a )}}

20 lo g_{10} (\frac{1}{k}) = 17.1

y, ln (y) = - 2 t

lo g_{10} (x) = - 1.187087

lo g_{27} (x) = lo g_{3} (x) + 2

ln (x) = ln (4.52) + 1, 10 y - 1, 14 z

What is the answer to log_{a}(x)=-1/(ln(a)) ?
The answer to log_{a}(x)=-1/(ln(a)) is x=a^{-1/(ln(a))}