What is the answer to log_{8}(4x+1)=-1 ?

The answer to log_{8}(4x+1)=-1 is x=-7/32

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log_{8}(4x+1)=-1

lo g_{8} (4 x + 1) = - 1

x = - \frac{7}{32}

Decimal Notation

x = - 0.21875

Solution steps

lo g_{8} (4 x + 1) = - 1

Apply log rules

4 x + 1 = \frac{1}{8}

Solve

4 x + 1 = \frac{1}{8} : x = - \frac{7}{32}

x = - \frac{7}{32}

lo g_{10} (t) 2 + lo g_{t} (4) = 1

2 ln (x + 3) = 4

2 x = 2 ln (3 x)

lo g_{9} (x) = lo g_{3} (x)

ln (8^{x} - 1) = 0

What is the answer to log_{8}(4x+1)=-1 ?
The answer to log_{8}(4x+1)=-1 is x=-7/32
Solve for x: log_{8}(4x+1)=-1
The solution is x=-7/32