What are the solutions to the equation 2x*10((9-x)/5)=18 ?

The solutions to the equation 2x*10((9-x)/5)=18 are x=(3(3-sqrt(7)))/2 ,x=(3(3+sqrt(7)))/2

Find the zeros of 2x*10((9-x)/5)=18

The zeros of 2x*10((9-x)/5)=18 are x=(3(3-sqrt(7)))/2 ,x=(3(3+sqrt(7)))/2

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2 x \cdot 10 (\frac{9 - x}{5}) = 18

x = \frac{3 ( 3 - 7 )}{2}, x = \frac{3 ( 3 + 7 )}{2}

Solution steps

2 x \cdot 10 (\frac{9 - x}{5}) = 18

Expand

2 x \cdot 10 (\frac{9 - x}{5}) : - 4 x^{2} + 36 x

- 4 x^{2} + 36 x = 18

Move

18

to the left side

- 4 x^{2} + 36 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 4 ) ( - 18 )}{2 ( - 4 )}

3 6^{2} - 4 (- 4) (- 18) = 127

x_{1, 2} = \frac{- 36 \pm 12 7}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 36 + 12 7}{2 ( - 4 )}, x_{2} = \frac{- 36 - 12 7}{2 ( - 4 )}

x = \frac{- 36 + 12 7}{2 ( - 4 )} : \frac{3 ( 3 - 7 )}{2}

x = \frac{- 36 - 12 7}{2 ( - 4 )} : \frac{3 ( 3 + 7 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 3 - 7 )}{2}, x = \frac{3 ( 3 + 7 )}{2}

\frac{x - 4}{5} \geq 2

lo g_{4} (32)

(54 b)^{\frac{2}{3}}

\infty = \infty

((H - k) ω + (H - j) R ω) N

What are the solutions to the equation 2x*10((9-x)/5)=18 ?
The solutions to the equation 2x*10((9-x)/5)=18 are x=(3(3-sqrt(7)))/2 ,x=(3(3+sqrt(7)))/2
Find the zeros of 2x*10((9-x)/5)=18
The zeros of 2x*10((9-x)/5)=18 are x=(3(3-sqrt(7)))/2 ,x=(3(3+sqrt(7)))/2