What is the answer to log_{10}(x)+log_{10}(x-9)=2 ?

The answer to log_{10}(x)+log_{10}(x-9)=2 is x=(9+sqrt(481))/2

Solve for x: log_{10}(x)+log_{10}(x-9)=2

The solution is x=(9+sqrt(481))/2

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lo g_{10} (x) + lo g_{10} (x - 9) = 2

x = \frac{9 + 481}{2}

Decimal Notation

x = 15.46585 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x - 9) = 2

Apply log rules

x (x - 9) = 100

Solve

x (x - 9) = 100 : x = \frac{9 + 481}{2}, x = \frac{9 - 481}{2}

x = \frac{9 + 481}{2}, x = \frac{9 - 481}{2}

Verify Solutions:

x = \frac{9 + 481}{2}

True

, x = \frac{9 - 481}{2}

False

The solution is

x = \frac{9 + 481}{2}

x, ln (3 x) = R

lo g_{10} (x) = 1000000000

x, ln (x - y^{2}) = 0

2 + ln (x + 5) = 3

lo g_{2} (X + 3) = 4

What is the answer to log_{10}(x)+log_{10}(x-9)=2 ?
The answer to log_{10}(x)+log_{10}(x-9)=2 is x=(9+sqrt(481))/2
Solve for x: log_{10}(x)+log_{10}(x-9)=2
The solution is x=(9+sqrt(481))/2