What is the answer to solvefor x,ln(xy)+4x=15 ?

The answer to solvefor x,ln(xy)+4x=15 is x=(\W((4e^{15})/y))/(4)

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solvefor x,ln(xy)+4x=15

solve for

x, ln (x y) + 4 x = 15

x = \frac{W ( \frac{4 e ^{15}}{y} )}{4}

Solution steps

ln (x y) + 4 x = 15

Move

4 x

to the right side

ln (x y) = 15 - 4 x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x y)} = e^{15 - 4 x}

Simplify

e^{l n (x y)} : x y

x y = e^{15 - 4 x}

Solve

x y = e^{15 - 4 x} : x = \frac{W ( \frac{4 e ^{15}}{y} )}{4}

x = \frac{W ( \frac{4 e ^{15}}{y} )}{4}

Verify Solutions:

x = \frac{W ( \frac{4 e ^{15}}{y} )}{4}

True

The solution is

x = \frac{W ( \frac{4 e ^{15}}{y} )}{4}

10.26 = - lo g_{10} (x)

x, ln (y) = ln (x^{2}) + C

lo g_{10} (x) + lo g_{10} (x + 5) = 5

lo g_{10} (v) = a

lo g_{10} (x) = 11.5

What is the answer to solvefor x,ln(xy)+4x=15 ?
The answer to solvefor x,ln(xy)+4x=15 is x=(\W((4e^{15})/y))/(4)