What is the answer to log_{2}(x^2-2x)=8 ?

The answer to log_{2}(x^2-2x)=8 is x=1+sqrt(257),x=1-sqrt(257)

Solve for x: log_{2}(x^2-2x)=8

The solution is x=1+sqrt(257),x=1-sqrt(257)

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lo g_{2} (x^{2} - 2 x) = 8

x = 1 + 257, x = 1 - 257

Decimal Notation

x = 17.03121 \dots, x = - 15.03121 \dots

Solution steps

lo g_{2} (x^{2} - 2 x) = 8

Apply log rules

x^{2} - 2 x = 256

Solve

x^{2} - 2 x = 256 : x = 1 + 257, x = 1 - 257

x = 1 + 257, x = 1 - 257

lo g_{2} (x - 2) + lo g_{2} (x) = 2

11 lo g_{10} (z) = 11

40 = 8 ln (1.5 \cdot t - 2) + 3

lo g_{10} (x) = \frac{1.2}{x}

ln (x^{2} - 4) = 8

What is the answer to log_{2}(x^2-2x)=8 ?
The answer to log_{2}(x^2-2x)=8 is x=1+sqrt(257),x=1-sqrt(257)
Solve for x: log_{2}(x^2-2x)=8
The solution is x=1+sqrt(257),x=1-sqrt(257)