What is the answer to log_{10}(x)2+log_{10}(2x)=0 ?

The answer to log_{10}(x)2+log_{10}(2x)=0 is x= 1/(10^{(log_{10)(2))/3}}

Solve for x: log_{10}(x)2+log_{10}(2x)=0

The solution is x= 1/(10^{(log_{10)(2))/3}}

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lo g_{10} (x) 2 + lo g_{10} (2 x) = 0

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 2 )}{3}}}

Decimal Notation

x = 0.79370 \dots

Solution steps

lo g_{10} (x) \cdot 2 + lo g_{10} (2 x) = 0

Apply log rules

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 2 )}{3}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 2 )}{3}}}

1 = lo g_{10} (\frac{0.05}{x})

2 lo g_{2} (x^{5}) - lo g_{2} (x) = 6

- 1.258288333 = ln (x)

x, ln (x) = 3 ln (y) + 3 c

lo g_{a} (5 y - 4) - lo g_{a} (2 y) = 3

What is the answer to log_{10}(x)2+log_{10}(2x)=0 ?
The answer to log_{10}(x)2+log_{10}(2x)=0 is x= 1/(10^{(log_{10)(2))/3}}
Solve for x: log_{10}(x)2+log_{10}(2x)=0
The solution is x= 1/(10^{(log_{10)(2))/3}}