What are the solutions to the equation 2x^2+9=1 ?

The solutions to the equation 2x^2+9=1 are x=2i,x=-2i

Find the zeros of 2x^2+9=1

The zeros of 2x^2+9=1 are x=2i,x=-2i

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2 x^{2} + 9 = 1

x = 2 i, x = - 2 i

Solution steps

2 x^{2} + 9 = 1

Move

9

to the right side

2 x^{2} = - 8

Divide both sides by

2

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

- 6 x - 11 = 8 x - 3

\frac{4 x}{3} > 8 x - 20

x^{3} + 2 x^{2} - 9 x + 2

7^{n + 4} - 7^{n}

\frac{4 + 8}{2}

What are the solutions to the equation 2x^2+9=1 ?
The solutions to the equation 2x^2+9=1 are x=2i,x=-2i
Find the zeros of 2x^2+9=1
The zeros of 2x^2+9=1 are x=2i,x=-2i