What is the answer to ln(7x+32)+ln(4)=2ln(x) ?

The answer to ln(7x+32)+ln(4)=2ln(x) is x=32

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ln(7x+32)+ln(4)=2ln(x)

ln (7 x + 32) + ln (4) = 2 ln (x)

x = 32

Solution steps

ln (7 x + 32) + ln (4) = 2 ln (x)

Apply log rules

(7 x + 32) \cdot 4 = x^{2}

Solve

(7 x + 32) \cdot 4 = x^{2} : x = 32, x = - 4

x = 32, x = - 4

Verify Solutions:

x = 32

True

, x = - 4

False

The solution is

x = 32

1 = lo g_{10} (2 x^{2} + 3 x - 22)

lo g_{x - 8} (x^{2} - 16) = 2

lo g_{1} (x) = 1.755

lo g_{10} (3 x - 3) = 3

y, x = 10 lo g_{2} (y)

What is the answer to ln(7x+32)+ln(4)=2ln(x) ?
The answer to ln(7x+32)+ln(4)=2ln(x) is x=32
Solve for x: ln(7x+32)+ln(4)=2ln(x)
The solution is x=32