What is the answer to ln(t)-1.3527300000000…=0.0897700000000… ?

The answer to ln(t)-1.3527300000000…=0.0897700000000… is t=e^{1.4425}

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ln(t)-1.3527300000000…=0.0897700000000…

ln (t) - 1.3527300000000 \dots = 0.0897700000000 \dots

t = e^{1.4425}

Decimal Notation

t = 4.23126 \dots

Solution steps

ln (t) - 1.35273 \dots = 0.08977 \dots

Move

1.35273 \dots

to the right side

ln (t) = 1.4425

Apply log rules

t = e^{1.4425}

Verify Solutions:

t = e^{1.4425}

True

The solution is

t = e^{1.4425}

4.23 = 3.86 + lo g_{10} (x)

lo g_{3} (x) = lo g_{10} (9) (2 x + 7)

lo g_{10} (x) = 0.87064

lo g_{3} (x - 2) + lo g_{3} (4 x - 7) = 1

ln (x - 8) + ln (x + 1) = 0

What is the answer to ln(t)-1.3527300000000…=0.0897700000000… ?
The answer to ln(t)-1.3527300000000…=0.0897700000000… is t=e^{1.4425}
Solve for t: ln(t)-1.3527300000000…=0.0897700000000…
The solution is t=e^{1.4425}