What is the answer to log_{6}(2x^2-8x-6)=2 ?

The answer to log_{6}(2x^2-8x-6)=2 is x=7,x=-3

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log_{6}(2x^2-8x-6)=2

lo g_{6} (2 x^{2} - 8 x - 6) = 2

x = 7, x = - 3

Solution steps

lo g_{6} (2 x^{2} - 8 x - 6) = 2

Apply log rules

2 x^{2} - 8 x - 6 = 36

Solve

2 x^{2} - 8 x - 6 = 36 : x = 7, x = - 3

x = 7, x = - 3

- 4 - 13 = 5 - lo g_{10} (X) - 15 \cdot X

lo g_{10} (x) + lo g_{10} (50) = 3

3 lo g_{4} (x) - 2 = 0

40 = 6 lo g_{10} (x)

lo g_{10} (5) + 2 lo g_{10} (x) = 3

What is the answer to log_{6}(2x^2-8x-6)=2 ?
The answer to log_{6}(2x^2-8x-6)=2 is x=7,x=-3
Solve for x: log_{6}(2x^2-8x-6)=2
The solution is x=7,x=-3