What is the answer to ln((x+1)/(2x-3))=1 ?

The answer to ln((x+1)/(2x-3))=1 is x=(3e+1)/(2e-1)

Solve for x: ln((x+1)/(2x-3))=1

The solution is x=(3e+1)/(2e-1)

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ln (\frac{x + 1}{2 x - 3}) = 1

x = \frac{3 e + 1}{2 e - 1}

Decimal Notation

x = 2.06349 \dots

Solution steps

ln (\frac{x + 1}{2 x - 3}) = 1

Apply log rules

\frac{x + 1}{2 x - 3} = e^{1}

Multiply both sides by

2 x - 3

\frac{x + 1}{2 x - 3} (2 x - 3) = e^{1} (2 x - 3)

Simplify

x + 1 = e (2 x - 3)

Solve

x + 1 = e (2 x - 3) : x = \frac{3 e + 1}{2 e - 1}

x = \frac{3 e + 1}{2 e - 1}

Verify Solutions:

x = \frac{3 e + 1}{2 e - 1}

True

The solution is

x = \frac{3 e + 1}{2 e - 1}

lo g_{6} (w) = - 2

\frac{16}{3} lo g_{2} (x) = 32

x = - ln (x - 2)

lo g_{10} (2565 x) = 7

2 = ln (3 + c)

What is the answer to ln((x+1)/(2x-3))=1 ?
The answer to ln((x+1)/(2x-3))=1 is x=(3e+1)/(2e-1)
Solve for x: ln((x+1)/(2x-3))=1
The solution is x=(3e+1)/(2e-1)