What is factor j^2+18j+17 ?

The solution to factor j^2+18j+17 is (j+1)(j+17)

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factor j^2+18j+17

factor

j^{2} + 18 j + 17

(j + 1) (j + 17)

Solution steps

j^{2} + 18 j + 17

Break the expression into groups

= (j^{2} + j) + (17 j + 17)

Factor out

j

from

j^{2} + j : j (j + 1)

Factor out

17

from

17 j + 17 : 17 (j + 1)

= j (j + 1) + 17 (j + 1)

Factor out common term

j + 1

= (j + 1) (j + 17)

\frac{n}{2} - 1 < 3

\frac{x}{- 4} \leq - 7

∣ 7 - 2 x ∣ = 4

- 16 t^{2} + 100 t + 75 = 0

\frac{1 + \frac{3}{2}}{2}