What is the answer to ln(3x-1)=ln(2)+ln(4x-6) ?

The answer to ln(3x-1)=ln(2)+ln(4x-6) is x= 11/5

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ln(3x-1)=ln(2)+ln(4x-6)

ln (3 x - 1) = ln (2) + ln (4 x - 6)

x = \frac{11}{5}

Decimal Notation

x = 2.2

Solution steps

ln (3 x - 1) = ln (2) + ln (4 x - 6)

Apply log rules

3 x - 1 = 2 (4 x - 6)

Solve

3 x - 1 = 2 (4 x - 6) : x = \frac{11}{5}

x = \frac{11}{5}

Verify Solutions:

x = \frac{11}{5}

True

The solution is

x = \frac{11}{5}

lo g_{10} (4 x + 11) = 2

ln (x + 7) + ln (x - 7) = 0

5 lo g_{10} (x - 2) = 0

x^{4} ln (x^{- 4}) = 0

lo g_{3} (3 x + 1) + 4 lo g_{3} (2) = 2

What is the answer to ln(3x-1)=ln(2)+ln(4x-6) ?
The answer to ln(3x-1)=ln(2)+ln(4x-6) is x= 11/5
Solve for x: ln(3x-1)=ln(2)+ln(4x-6)
The solution is x= 11/5