What is the answer to log_{2}(x^2-1)=10^{10} ?

The answer to log_{2}(x^2-1)=10^{10} is x=sqrt(2^{10^{10)}+1},x=-sqrt(2^{10^{10)}+1}

Solve for x: log_{2}(x^2-1)=10^{10}

The solution is x=sqrt(2^{10^{10)}+1},x=-sqrt(2^{10^{10)}+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x^{2} - 1) = 1 0^{10}

x = 2^{1 0^{10}} + 1, x = - 2^{1 0^{10}} + 1

Solution steps

lo g_{2} (x^{2} - 1) = 1 0^{10}

Apply log rules

x^{2} - 1 = 2^{1 0^{10}}

Solve

x^{2} - 1 = 2^{1 0^{10}} : x = 2^{1 0^{10}} + 1, x = - 2^{1 0^{10}} + 1

x = 2^{1 0^{10}} + 1, x = - 2^{1 0^{10}} + 1

ln (x) = - \frac{1}{20}

lo g_{10} (x) = - 0.33

x, lo g_{2} (x + y) = 3

lo g_{10} (a) = 0.19

lo g_{10} (x + 2) - lo g_{10} (x) = 3

What is the answer to log_{2}(x^2-1)=10^{10} ?
The answer to log_{2}(x^2-1)=10^{10} is x=sqrt(2^{10^{10)}+1},x=-sqrt(2^{10^{10)}+1}
Solve for x: log_{2}(x^2-1)=10^{10}
The solution is x=sqrt(2^{10^{10)}+1},x=-sqrt(2^{10^{10)}+1}