What is the answer to log_{10}(x)-log_{10}(2-x)=0 ?

The answer to log_{10}(x)-log_{10}(2-x)=0 is x=1

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log_{10}(x)-log_{10}(2-x)=0

lo g_{10} (x) - lo g_{10} (2 - x) = 0

x = 1

Solution steps

lo g_{10} (x) - lo g_{10} (2 - x) = 0

Add

lo g_{10} (2 - x)

to both sides

lo g_{10} (x) - lo g_{10} (2 - x) + lo g_{10} (2 - x) = 0 + lo g_{10} (2 - x)

Simplify

lo g_{10} (x) = lo g_{10} (2 - x)

Apply log rules

x = 2 - x

Solve

x = 2 - x : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{10} (x + 5) = 1

lo g_{10} (x + 5) = 3

lo g_{10} (x) = 0.0377

lo g_{a} (6) = 0.5

lo g_{10} (x) = - 0.74

What is the answer to log_{10}(x)-log_{10}(2-x)=0 ?
The answer to log_{10}(x)-log_{10}(2-x)=0 is x=1
Solve for x: log_{10}(x)-log_{10}(2-x)=0
The solution is x=1