What is the answer to ln(x)=1-ln(x+2) ?

The answer to ln(x)=1-ln(x+2) is x=(-2+sqrt(4+4e))/2

Solve for x: ln(x)=1-ln(x+2)

The solution is x=(-2+sqrt(4+4e))/2

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ln (x) = 1 - ln (x + 2)

x = \frac{- 2 + 4 + 4 e}{2}

Decimal Notation

x = 0.92828 \dots

Solution steps

ln (x) = 1 - ln (x + 2)

Add

ln (x + 2)

to both sides

ln (x) + ln (x + 2) = 1 - ln (x + 2) + ln (x + 2)

Simplify

ln (x) + ln (x + 2) = 1

Apply log rules

x (x + 2) = e

Solve

x (x + 2) = e : x = \frac{- 2 + 4 + 4 e}{2}, x = \frac{- 2 - 4 + 4 e}{2}

x = \frac{- 2 + 4 + 4 e}{2}, x = \frac{- 2 - 4 + 4 e}{2}

Verify Solutions:

x = \frac{- 2 + 4 + 4 e}{2}

True

, x = \frac{- 2 - 4 + 4 e}{2}

False

The solution is

x = \frac{- 2 + 4 + 4 e}{2}

a, lo g_{a} (mn) = 16

\frac{9}{8} lo g_{2} (x) = - 4

2 + ln (x + 1) = 0

25 = 10 lo g_{10} (S)

ln (4) + ln (x + 2) = ln (9)

What is the answer to ln(x)=1-ln(x+2) ?
The answer to ln(x)=1-ln(x+2) is x=(-2+sqrt(4+4e))/2
Solve for x: ln(x)=1-ln(x+2)
The solution is x=(-2+sqrt(4+4e))/2