What is the answer to 0=80-9log_{10}(t+1) ?

The answer to 0=80-9log_{10}(t+1) is t=100000000*10^{8/9}-1

Solve for t: 0=80-9log_{10}(t+1)

The solution is t=100000000*10^{8/9}-1

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0 = 80 - 9 lo g_{10} (t + 1)

t = 100000000 \cdot 1 0^{\frac{8}{9}} - 1

Decimal Notation

t = 774263681.681127

Solution steps

0 = 80 - 9 lo g_{10} (t + 1)

Switch sides

80 - 9 lo g_{10} (t + 1) = 0

Move

80

to the right side

- 9 lo g_{10} (t + 1) = - 80

Divide both sides by

- 9

lo g_{10} (t + 1) = \frac{80}{9}

Apply log rules

t + 1 = 100000000 \cdot 1 0^{\frac{8}{9}}

Solve

t + 1 = 100000000 \cdot 1 0^{\frac{8}{9}} : t = 100000000 \cdot 1 0^{\frac{8}{9}} - 1

t = 100000000 \cdot 1 0^{\frac{8}{9}} - 1

Verify Solutions:

t = 100000000 \cdot 1 0^{\frac{8}{9}} - 1

True

The solution is

t = 100000000 \cdot 1 0^{\frac{8}{9}} - 1

lo g_{27} (x) = \frac{- 1}{3}

lo g_{x} (\frac{1}{2187}) = 7

x, lo g_{4} (3 x) = 2.2

lo g_{10} (2 x + 4) = 3

lo g_{10} (2 x + 4) = 4

What is the answer to 0=80-9log_{10}(t+1) ?
The answer to 0=80-9log_{10}(t+1) is t=100000000*10^{8/9}-1
Solve for t: 0=80-9log_{10}(t+1)
The solution is t=100000000*10^{8/9}-1