What is the answer to 3log_{2}(x+1)-2=13 ?

The answer to 3log_{2}(x+1)-2=13 is x=31

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3log_{2}(x+1)-2=13

3 lo g_{2} (x + 1) - 2 = 13

x = 31

Solution steps

3 lo g_{2} (x + 1) - 2 = 13

Move

2

to the right side

3 lo g_{2} (x + 1) = 15

Divide both sides by

3

lo g_{2} (x + 1) = 5

Apply log rules

x + 1 = 32

Solve

x + 1 = 32 : x = 31

x = 31

Verify Solutions:

x = 31

True

The solution is

x = 31

30 = 20 lo g_{10} (\frac{x}{20})

x, y = \frac{ln ( x y )}{x}

ln (2^{x}) + x = 3

lo g_{10} (9 x) = \frac{3}{2}

lo g_{4} (3 x) - 1 = lo g_{4 - 2 + 9} (x)

What is the answer to 3log_{2}(x+1)-2=13 ?
The answer to 3log_{2}(x+1)-2=13 is x=31
Solve for x: 3log_{2}(x+1)-2=13
The solution is x=31