What is the answer to ln(3)+ln(2x^2+4)=ln(12) ?

The answer to ln(3)+ln(2x^2+4)=ln(12) is x=0

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ln(3)+ln(2x^2+4)=ln(12)

ln (3) + ln (2 x^{2} + 4) = ln (12)

x = 0

Solution steps

ln (3) + ln (2 x^{2} + 4) = ln (12)

Move

ln (3)

to the right side

ln (2 x^{2} + 4) = ln (12) - ln (3)

Apply log rules

2 x^{2} + 4 = 4

Solve

2 x^{2} + 4 = 4 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

- 10 + lo g_{3} (x + 3) = - 10

0.9999 = 10 lo g_{10} (x)

2 ln (\frac{x}{3 - x}) = ln (4)

3 = lo g_{5} (5 x + 3)

ln (x) \frac{2 + 3}{2} = 8

What is the answer to ln(3)+ln(2x^2+4)=ln(12) ?
The answer to ln(3)+ln(2x^2+4)=ln(12) is x=0
Solve for x: ln(3)+ln(2x^2+4)=ln(12)
The solution is x=0