What is the answer to 1+2log_{3}(x)=log_{3}(28x-9) ?

The answer to 1+2log_{3}(x)=log_{3}(28x-9) is x=9,x= 1/3

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1+2log_{3}(x)=log_{3}(28x-9)

1 + 2 lo g_{3} (x) = lo g_{3} (28 x - 9)

x = 9, x = \frac{1}{3}

Decimal Notation

x = 9, x = 0.33333 \dots

Solution steps

1 + 2 lo g_{3} (x) = lo g_{3} (28 x - 9)

Apply log rules

3 x^{2} = 28 x - 9

Solve

3 x^{2} = 28 x - 9 : x = 9, x = \frac{1}{3}

x = 9, x = \frac{1}{3}

Verify Solutions:

x = 9

True

, x = \frac{1}{3}

True

The solutions are

x = 9, x = \frac{1}{3}

ln (10 - 3 x) = ln (- 4 x)

5 + ln (x + 3) = 2

5 ln (x) = ln (x^{2})

lo g_{10} (x^{2}) = - 5

3 = lo g_{a} (y)

What is the answer to 1+2log_{3}(x)=log_{3}(28x-9) ?
The answer to 1+2log_{3}(x)=log_{3}(28x-9) is x=9,x= 1/3
Solve for x: 1+2log_{3}(x)=log_{3}(28x-9)
The solution is x=9,x= 1/3