What is the answer to log_{5}(2x+23)=log_{5}(x-5) ?

The answer to log_{5}(2x+23)=log_{5}(x-5) is No Solution for x\in\mathbb{R}

Solve for x: log_{5}(2x+23)=log_{5}(x-5)

The solution is No Solution for x\in\mathbb{R}

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lo g_{5} (2 x + 23) = lo g_{5} (x - 5)

No Solution for x \in R

Solution steps

lo g_{5} (2 x + 23) = lo g_{5} (x - 5)

Apply log rules

2 x + 23 = x - 5

Solve

2 x + 23 = x - 5 : x = - 28

x = - 28

Verify Solutions:

x = - 28

False

The solution is

No Solution for x \in R

lo g_{5} (x^{2} - 9 x + 15) = 2

- 8.66 ln (x) + 8.66 ln (0.6) + 15 = 0

lo g_{16} (3 x) = lo g_{16} (x + 10)

0 = ln (x) + 3

- 6 = 9 - lo g_{10} ((3 - x)^{3})

What is the answer to log_{5}(2x+23)=log_{5}(x-5) ?
The answer to log_{5}(2x+23)=log_{5}(x-5) is No Solution for x\in\mathbb{R}
Solve for x: log_{5}(2x+23)=log_{5}(x-5)
The solution is No Solution for x\in\mathbb{R}