What is the answer to 2=-log_{10}(t) ?

The answer to 2=-log_{10}(t) is t= 1/100

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2=-log_{10}(t)

2 = - lo g_{10} (t)

t = \frac{1}{100}

Decimal Notation

t = 0.01

Solution steps

2 = - lo g_{10} (t)

Move

lo g_{10} (t)

to the left side

2 + lo g_{10} (t) = 0

Move

2

to the right side

lo g_{10} (t) = - 2

Apply log rules

t = \frac{1}{100}

Verify Solutions:

t = \frac{1}{100}

True

The solution is

t = \frac{1}{100}

7.3 = 20 lo g_{10} (\frac{4.7}{x})

- 30 = 10 \cdot lo g_{10} (w)

ln (x) - 3 + 2 x = 0

x, z = ln (x y)

3 lo g_{5} (4 x + 1) = 6