What is the answer to log_{10}(1-6x)=1 ?

The answer to log_{10}(1-6x)=1 is x=-3/2

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log_{10}(1-6x)=1

lo g_{10} (1 - 6 x) = 1

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

lo g_{10} (1 - 6 x) = 1

Apply log rules

1 - 6 x = 10

Solve

1 - 6 x = 10 : x = - \frac{3}{2}

x = - \frac{3}{2}

ln (x \cdot y) = ln (x) + ln (y)

x, lo g_{x} (125) = 3

lo g_{2} (3 x) = x - 1

5402 = - ln (1 - x)

x, 3 = lo g_{10} (x)

What is the answer to log_{10}(1-6x)=1 ?
The answer to log_{10}(1-6x)=1 is x=-3/2
Solve for x: log_{10}(1-6x)=1
The solution is x=-3/2