What are the solutions to the equation b^2+5=8b-10 ?

The solutions to the equation b^2+5=8b-10 are b=5,b=3

Find the zeros of b^2+5=8b-10

The zeros of b^2+5=8b-10 are b=5,b=3

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b^{2} + 5 = 8 b - 10

b = 5, b = 3

Solution steps

b^{2} + 5 = 8 b - 10

Move

10

to the left side

b^{2} + 15 = 8 b

Move

8 b

to the left side

b^{2} + 15 - 8 b = 0

Write in the standard form

a x^{2} + b x + c = 0

b^{2} - 8 b + 15 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

b_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, b_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

b = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

b = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

b = 5, b = 3

(2)^{\frac{1}{3}}

- \frac{1}{2} (5 x - 8) \geq - 6

\frac{2}{\frac{3}{\frac{1}{3}}}

6 x^{2} - 7 x - 124 = 0

(0)^{2}

What are the solutions to the equation b^2+5=8b-10 ?
The solutions to the equation b^2+5=8b-10 are b=5,b=3
Find the zeros of b^2+5=8b-10
The zeros of b^2+5=8b-10 are b=5,b=3