What is the answer to log_{10}((2x+1)/(x-1))=0 ?

The answer to log_{10}((2x+1)/(x-1))=0 is x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}((2x+1)/(x-1))=0

lo g_{10} (\frac{2 x + 1}{x - 1}) = 0

x = - 2

Solution steps

lo g_{10} (\frac{2 x + 1}{x - 1}) = 0

Apply log rules

\frac{2 x + 1}{x - 1} = 1 0^{0}

Multiply both sides by

x - 1

\frac{2 x + 1}{x - 1} (x - 1) = 1 0^{0} (x - 1)

Simplify

2 x + 1 = x - 1

Solve

2 x + 1 = x - 1 : x = - 2

x = - 2

Verify Solutions:

x = - 2

True

The solution is

x = - 2

- \frac{7}{18} = ln (x) 7

\frac{1}{lo g _{2} ( x )} = 5

\frac{1}{lo g _{2} ( x )} = 1

lo g_{e} (\frac{5}{x}) = 0.868

lo g_{10} (3 y - 1) = 0

What is the answer to log_{10}((2x+1)/(x-1))=0 ?
The answer to log_{10}((2x+1)/(x-1))=0 is x=-2
Solve for x: log_{10}((2x+1)/(x-1))=0
The solution is x=-2