What is the answer to log_{3}(x^2-x-5)=2 ?

The answer to log_{3}(x^2-x-5)=2 is x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2

Solve for x: log_{3}(x^2-x-5)=2

The solution is x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2

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lo g_{3} (x^{2} - x - 5) = 2

x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

Decimal Notation

x = 4.27491 \dots, x = - 3.27491 \dots

Solution steps

lo g_{3} (x^{2} - x - 5) = 2

Apply log rules

x^{2} - x - 5 = 9

Solve

x^{2} - x - 5 = 9 : x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

x, ln (\frac{15}{x}) = 0

1.023 = ln (\frac{0.01667}{a})

lo g_{4} (4 x + 2) - lo g_{4} (4 - x) = 1

lo g_{6} (a) = 3

lo g_{3} (x^{2} - 16) = 2

What is the answer to log_{3}(x^2-x-5)=2 ?
The answer to log_{3}(x^2-x-5)=2 is x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2
Solve for x: log_{3}(x^2-x-5)=2
The solution is x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2